Fast Growing Hierarchy Calculator High Quality May 2026

A high‑quality FGH calculator can be extended:


Use recursion with caching of ( f_\alpha(n) ) for small ( \alpha, n ).

from functools import lru_cache

@lru_cache(maxsize=None) def f(alpha, n): if n == 0: return 0 # or 1, depending on convention if alpha == 0: return n + 1 if is_successor(alpha): pred = predecessor(alpha) # iterate n times result = n for _ in range(n): result = f(pred, result) return result else: # limit return f(fund(alpha, n), n) fast growing hierarchy calculator high quality

Problem: This recursion is extremely deep for moderate n (e.g., ( f_\omega+1(3) ) already huge).
So high‑quality calculators must: A high‑quality FGH calculator can be extended:


def fgh(alpha, n, limit_ordinal_fundamental=None):
    """
    Compute f_alpha(n) with custom fundamental sequences.
Args:
    alpha: int or callable for limit ordinals returning alpha[n]
    n: int >= 0
    limit_ordinal_fundamental: function(alpha, n) -> alpha_n
"""
if alpha == 0:
    return n + 1
if isinstance(alpha, int):  # successor
    result = n
    for _ in range(n):
        result = fgh(alpha - 1, result, limit_ordinal_fundamental)
    return result
# limit ordinal
if limit_ordinal_fundamental:
    alpha_n = limit_ordinal_fundamental(alpha, n)
    return fgh(alpha_n, n, limit_ordinal_fundamental)
raise ValueError(f"No fundamental sequence for alpha")

If you are a developer wanting to create the ultimate FGH calculator, or a user hoping to locate one, here is the blueprint.

For inputs like ( f_\omega+1(4) ), the output is astronomically large (beyond power towers). A high-quality calculator does not attempt to print 10^10^... digits. Instead, it outputs: Use recursion with caching of ( f_\alpha(n) )

Replace recursion with a stack machine to avoid recursion limits:

Input: (alpha, n)
Stack = [(alpha, n)]
While stack not empty:
    Pop (a, m)
    if m == 0 → push result
    else reduce a to a[m-1] …

This module handles the transfinite ordinals ($\omega, \omega+1, \omega \cdot 2, \omega^2, \epsilon_0$).

Requirements:

  • Fundamental Sequence Logic: For limit ordinals, the system must determine $\lambda[n]$.
  • What does "high quality" actually mean in this context? Let us break down the indispensable features.