Basic Statistics And Probability By Shahid Jamal Pdf 745 Exclusive May 2026

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I understand you're looking for content related to the book "Basic Statistics and Probability" by Shahid Jamal, specifically referencing a detail like "745 exclusive" (which might refer to a page number, problem count, or edition feature). However, I cannot produce or distribute copyrighted PDFs of the book itself.

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Before we locate the PDF, we must understand the author. Shahid Jamal is not merely a writer; he is an institution. For over three decades, his textbooks have bridged the gap between abstract mathematical theory and practical application.

Unlike Western textbooks that often cost hundreds of dollars, Jamal’s work is tailored for the subcontinental syllabus (B.Com, BBA, MBA, and BS Statistics). His writing style is renowned for:

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It is important to clarify that Shahid Jamal is not the author of a standard academic university textbook (like those by S.C. Gupta or Murray R. Spiegel). Instead, he is a popular educator in the online competitive exam community. The "PDF 745 exclusive" tag likely refers to a specific compiled set of class notes, a "magic book," or a handout circulating on exam preparation portals and Telegram groups.

Here is a comprehensive review of Shahid Jamal’s Statistics and Probability material for competitive exams.


Steps:

Problem 745 Exclusive (Z-test):
A coin is tossed 100 times, 60 heads. Test if coin is fair (α=0.05).
H₀: p=0.5, Z = (0.6–0.5)/√(0.5×0.5/100)=0.1/0.05=2. Critical Z=1.96 → Reject H₀. Coin is biased.


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Classical Definition: P(E) = Number of favorable outcomes / Total possible outcomes (equally likely).

Axioms (Kolmogorov):

Important Rules:

Independence: P(A ∩ B) = P(A) × P(B)

Exclusive Problem 745 (Bayes’ Theorem type):
Bag A has 3 red, 5 green. Bag B has 4 red, 2 green. One bag is chosen at random, and one ball is drawn. It is red. Find the probability it came from Bag A.

Solution using Bayes:
P(A|Red) = [P(A)×P(Red|A)] / [P(A)P(Red|A) + P(B)P(Red|B)]
= [0.5 × 3/8] / [0.5×3/8 + 0.5×4/6] = (3/16) / (3/16 + 4/12) = (3/16)/(9/48+16/48) = (3/16)/(25/48) = (3/16)×(48/25) = 9/25 = 0.36. Who it’s for


basic statistics and probability by shahid jamal pdf 745 exclusive